Given the updated information about the register sizes and the initial content of the PC register, let's incorporate these details into the explanation:
1. LODA A (Load the content of Memory location A into the Accumulator Register):
- The instruction is fetched from memory location (11FE)h.
- The 32-bit instruction is loaded into the IR (Instruction Register).
- The opcode is the first 16 bits of the instruction, and the operand (address) is the next 16 bits.
- The address (4321)h is used to fetch the content from memory.
- The content is loaded into the MBR (Memory Buffer Register).
- The content from MBR is then loaded into the Accumulator Register (AC).
2.ADD B (Add the content of memory location B to the Accumulator Register):
- The instruction is fetched from memory location (11FF)h.
- The 32-bit instruction is loaded into the IR.
- The opcode is the first 16 bits of the instruction, and the operand (address) is the next 16 bits.
- The address (1FFE)h is used to fetch the content from memory.
- The content is added to the value already in the AC.
3. STOR C (Stores the content of Accumulator register to memory location C):
- The instruction is fetched from memory location (2000)h.
- The 32-bit instruction is loaded into the IR.
- The opcode is the first 16 bits of the instruction, and the operand (address) is the next 16 bits.
- The content of the AC is stored in memory at the address (0000)h.
Registers:
- AC (Accumulator Register): 16 bits
- PC (Program Counter): 16 bits, initialized with (11FE)h
- MAR (Memory Address Register): 16 bits
- MBR (Memory Buffer Register): 16 bits
- IR (Instruction Register): 32 bits
This explanation considers the register sizes and the initial content of the PC register. The execution steps involve fetching instructions, fetching data from memory based on addresses, performing operations, and storing results back in memory using the specified registers.
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