To create logic circuits for the given Boolean expressions, we need to simplify the expressions first. Let's simplify each expression and then create the logic circuits.

i) \( (xyz) + (xyz)' + (xz'y) \)

Using the fact that \( (A + A') \) is always true, the first two terms simplify to \( 1 \):

\[ (xyz) + (xyz)' = 1 \]

So the expression simplifies to \( 1 + (xz'y) \). This expression is always true, so the logic circuit is just a constant '1'.

ii) \( (x'yz) (xyz') (xy'z) \)

Using Boolean algebra laws, we can simplify this expression:

\[ (x'yz) (xyz') (xy'z) = x'yy'z + xyy'z + x'y'yy'z + x'y'y'z \]

Simplifying further:

\[ 0 + 0 + 0 + x'y'y'z = x'y'y'z \]

So the simplified expression is \( x'y'y'z \). The logic circuit for this expression would involve three AND gates (for \( x' \), \( y' \), and \( z \)) and one OR gate.

If you have a specific way you'd like these circuits represented (e.g., using logic gates symbols), please let me know, and I can provide a more detailed representation.

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