However, this machine is different from the example of Figure 4 in the following ways:  Each memory word of this new machine is of 16 bits in length.  Each instruction is of length 32 bits with 16 bits for operation code (opcode) and 16 bits for specifying one direct operand.  The Main Memory of the machine would be of size 216 words.  The three consecutive instructions are placed starting from memory location (11FE)h ; operand A is at location (1FFF)h and contains a value (4321)h, Operand B is at location (2000)h and contains a value (1FFE)h and operand C is at location (2001)h and contains a value (0000)h.

 Thank you for providing additional details about the machine architecture. Based on the new information, let's adapt the explanation for the execution of the three consecutive instructions using the modified machine:

1. LODA A (Load the content of Memory location A into the Accumulator Register):

   - The instruction is fetched from memory location (11FE)h.

   - The opcode is the first 16 bits of the instruction, and the operand (address) is the next 16 bits.

   - The address (4321)h is used to fetch the content from memory.

   - The content is loaded into the Accumulator Register.

2. ADD B (Add the content of memory location B to the Accumulator Register):

   - The instruction is fetched from memory location (11FF)h.

   - The opcode is the first 16 bits of the instruction, and the operand (address) is the next 16 bits.

   - The address (1FFE)h is used to fetch the content from memory.

   - The content is added to the value already in the Accumulator Register.

3. STOR C (Stores the content of Accumulator register to memory location C):

   - The instruction is fetched from memory location (2000)h.

   - The opcode is the first 16 bits of the instruction, and the operand (address) is the next 16 bits.

   - The address (0000)h is used to store the content of the Accumulator Register back into memory.

Given the memory organization, each memory word is 16 bits, and each instruction is 32 bits with 16 bits for the opcode and 16 bits for the operand. The main memory has a size of 2^16 words. The operands A, B, and C are stored at specific memory locations with their respective values.

Please note that the actual execution would involve additional steps depending on the specific microarchitecture, addressing modes, and instruction set architecture of the machine, which may not be fully detailed in the provided information.